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Well, I always feel so familiarDDoS attacks can be divided into many different forms. These forms include flood attacks and more sophisticated application layer attack methods/tools. Flood attacks rely on a large amount of traffic/sessions to deplete a target, such as TCP SYN, ICMP, and UDP floods; Advanced application layer attack methods/tools include Slowloris, KillApache, etc.What if there is a third level of support? . Is xun yu's help.其实此事完全可以请教张良先生，可韩信并未这么做。This is the first sub!Code as above; Write three functions of order500, order200 and orderNormal respectively, and process their own business logic in the functions respectively. If their own functions cannot be processed, they will return the string nextSuccessor to pass it back, then encapsulate the constructor Chain, pass an object fn into it, and have their own attribute Successor. There are two methods setNextSuccessor and passRequest on the prototype. The method setNextSuccessor specifies the order of nodes in the responsibility chain, and saves the corresponding method to the attribute this.Successor, chainOrder500. SetNextSuccessor (chainOrder200); ChainOrder200. SetNextSuccessor (chainOrderNormal); Specifies the order in the chain, so this.Successor references the order200 method and the orderNormal method, so if chainOrder500.passRequest (1, true, 500) is called for the first time, the order500 method is called, output directly, and chainOrder500.passRequ is called for the second time.林赛·沃尔特斯（乔丹·莱德 Jordan Ladd 饰）和她最好的朋友妮可（妮可·摩尔 Nicole Moore 饰）决定一同抢劫林赛的丈夫塞斯（Tom DeNucci 饰），并且进行一场疯狂的犯罪狂欢，而布朗扎警探（汤姆·塞兹摩尔 Tom Sizemore 饰）则将解决这个乱子。 
　　每个盗贼都需要一个逃亡计划…一个逃避婚姻的女人和她最好的朋友，意图抢走她丈夫的财产…琳赛和尼科儿这两个朋友，决定向免费电影琳赛的丈夫赛特展开复仇。酝酿着计划要抢走他所有的财产，离开城市逃亡，2个女孩进行着他们的南向计划。随着当地的侦探循着线索追赶他们，他们的友谊变得岌岌可危，琳赛和尼科儿是否能达成他们完美生活的目标，或者这个计划将会导致他们的死亡？